$\sqrt[n]{a}=b\phantom{\rule{0.147em}{0ex}},\phantom{\rule{0.147em}{0ex}}\mathrm{ja}{\phantom{\rule{0.588em}{0ex}}b}^{n}=a$
$\begin{array}{l}\sqrt[4]{16}=2\phantom{\rule{0.147em}{0ex}},\phantom{\rule{0.441em}{0ex}}\mathit{jo}\phantom{\rule{0.147em}{0ex}}{2}^{4}=16\\ \\ \sqrt[3]{-0,001}=-0,1\phantom{\rule{0.147em}{0ex}},\phantom{\rule{0.294em}{0ex}}\mathit{jo}\phantom{\rule{0.441em}{0ex}}{\left(-0,1\right)}^{3}=-0,001\\ \\ \sqrt[13]{1}=1,\phantom{\rule{0.294em}{0ex}}\mathit{jo}\phantom{\rule{0.294em}{0ex}}{1}^{13}=1\\ \\ \sqrt[26]{0}=0,\phantom{\rule{0.294em}{0ex}}\mathit{jo}\phantom{\rule{0.147em}{0ex}}{0}^{26}=0\end{array}$
$\sqrt[n]{1}=1$    $\sqrt[n]{0}=0$
$\sqrt[n]{{a}^{m}}={a}^{\frac{m}{n}}$ jeb ${a}^{\frac{m}{n}}=\sqrt[n]{{a}^{m}}$
$\begin{array}{l}\phantom{\rule{0.147em}{0ex}}\sqrt[2]{3}=\phantom{\rule{0.147em}{0ex}}{3}^{\frac{1}{2}}\phantom{\rule{0.147em}{0ex}}\phantom{\rule{0.147em}{0ex}}\phantom{\rule{0.147em}{0ex}}\phantom{\rule{0.147em}{0ex}}\phantom{\rule{0.147em}{0ex}}\phantom{\rule{0.147em}{0ex}}\phantom{\rule{0.147em}{0ex}}\phantom{\rule{0.147em}{0ex}}\phantom{\rule{0.147em}{0ex}}\phantom{\rule{0.147em}{0ex}}\phantom{\rule{0.147em}{0ex}}\phantom{\rule{0.147em}{0ex}}\\ \sqrt[5]{{2}^{3}}={2}^{\frac{3}{5}}\phantom{\rule{0.147em}{0ex}}\phantom{\rule{0.147em}{0ex}}\phantom{\rule{0.147em}{0ex}}\phantom{\rule{0.147em}{0ex}}\phantom{\rule{0.147em}{0ex}}\phantom{\rule{0.147em}{0ex}}\phantom{\rule{0.147em}{0ex}}\phantom{\rule{0.147em}{0ex}}\phantom{\rule{0.147em}{0ex}}\phantom{\rule{0.147em}{0ex}}\phantom{\rule{0.147em}{0ex}}\phantom{\rule{0.147em}{0ex}}\phantom{\rule{0.147em}{0ex}}\phantom{\rule{0.147em}{0ex}}\phantom{\rule{0.147em}{0ex}}\end{array}$
$\begin{array}{l}\phantom{\rule{0.147em}{0ex}}{27}^{\frac{1}{3}}=\sqrt[3]{27}=3\\ \\ {81}^{\frac{3}{4}}=\sqrt[4]{{81}^{3}}={\left(\sqrt[4]{81}\right)}^{3}={3}^{3}=27\end{array}$